290. Word Pattern

https://leetcode.com/problems/word-pattern/

Python

class Solution:
    def wordPattern(self, pattern: str, s: str) -> bool:
        mapper = dict()
        words = s.split(' ')

        if len(pattern) != len(words):
            return False

        for p, word in zip(pattern, words):
            if word not in mapper:
                mapper[word] = p
                continue

            if mapper[word] != p:
                return False

        return len(mapper.values()) == len(set(mapper.values()))